Mirror Equation Video Lessons

Concept

# Problem: 1) An object is 1.0 cm tall and its inverted image is 3.0 cm tall. What is the exact magnification?2) A ______________ can be considered as an ultrathin beam of light that travels in a straight line until it meets a reflecting or refracting surface.

###### FREE Expert Solution

Magnification:

$\overline{){\mathbf{m}}{\mathbf{=}}\frac{{\mathbf{h}}_{\mathbf{i}}}{{\mathbf{h}}_{\mathbf{o}}}{\mathbf{=}}{\mathbf{-}}\frac{{\mathbf{s}}_{\mathbf{i}}}{{\mathbf{s}}_{\mathbf{o}}}}$

1)

hi = - 3.0 cm (Image height).

ho = 1.0 cm (Object height)

79% (448 ratings)
###### Problem Details

1) An object is 1.0 cm tall and its inverted image is 3.0 cm tall. What is the exact magnification?

2) A ______________ can be considered as an ultrathin beam of light that travels in a straight line until it meets a reflecting or refracting surface.