Problem: As a spherical mirror becomes flatter, the radius of curvature R gets larger. Notice that as R goes to infinity, so does f, because f = R/2. Thus, as R gets larger, 1/f gets smaller. In the limit where you allow R to go infinity, 1/f becomes zero. Therefore, if you could construct a mirror with an infinitely large radius of curvature, it would obey the equation 1/so + 1/si = 0.What is the value of si obtained from this new equation? Express your answer in terms of so.

FREE Expert Solution

Lens equation:
1so+1si=1f

View Complete Written Solution
Problem Details

As a spherical mirror becomes flatter, the radius of curvature R gets larger. Notice that as R goes to infinity, so does f, because f = R/2. Thus, as R gets larger, 1/f gets smaller. In the limit where you allow R to go infinity, 1/f becomes zero. Therefore, if you could construct a mirror with an infinitely large radius of curvature, it would obey the equation 1/so + 1/si = 0.


What is the value of si obtained from this new equation? Express your answer in terms of so.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Thin Lens And Lens Maker Equations concept. You can view video lessons to learn Thin Lens And Lens Maker Equations. Or if you need more Thin Lens And Lens Maker Equations practice, you can also practice Thin Lens And Lens Maker Equations practice problems.