Lens equation:

$\overline{)\frac{\mathbf{1}}{{\mathit{s}}_{\mathit{o}}}{\mathbf{+}}\frac{\mathbf{1}}{{\mathit{s}}_{\mathit{i}}}{\mathbf{=}}\frac{\mathbf{1}}{\mathit{f}}}$

As a spherical mirror becomes flatter, the radius of curvature *R* gets larger. Notice that as *R* goes to infinity, so does *f*, because *f* = R/2. Thus, as R gets larger, 1/*f* gets smaller. In the limit where you allow *R* to go infinity, 1/*f* becomes zero. Therefore, if you could construct a mirror with an infinitely large radius of curvature, it would obey the equation 1/s_{o} + 1/s_{i} = 0.

What is the value of s_{i} obtained from this new equation? Express your answer in terms of *s _{o}*.

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