Problem: The following nuclei are observed to decay by emitting an α particle: 239/94Pu.Part AWrite out the decay process for 239/94Pu.Part BDetermine the energy released in this reaction.

FREE Expert Solution

For an α-decay, the mass number of the nucleus is always reduced by 4 and the charge number reduced by 2 for the given nucleus.

The energy released in the reaction:

E=(m)(931.5MeV)

Part A

The decay process for 239/94Pu is:

 94Pu2392He4 + 92U235 + ΔE

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Problem Details

The following nuclei are observed to decay by emitting an α particle: 239/94Pu.

Part A

Write out the decay process for 239/94Pu.

Part B

Determine the energy released in this reaction.

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