Photon energy:

$\overline{){\mathbf{E}}{\mathbf{=}}{\mathbf{h}}{\mathbf{f}}{\mathbf{=}}\frac{\mathbf{h}\mathbf{c}}{\mathbf{\lambda}}}$

1GHz = 10^{9}Hz

1eV = 1.6 × 10^{-19} J

f = 2.60GHz(10^{9}Hz/1GHz) = 2.60 × 10^{9} Hz

Calculate the energy, in electron volts, of a photon whose frequency is the following.

2.60 GHz

____ eV

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