Magnetic force on a current-carrying conductor:

$\overline{){{\mathbf{F}}}_{{\mathbf{B}}}{\mathbf{=}}{\mathbf{B}}{\mathbf{i}}{\mathbf{L}}}$

Magnetic field around a wire carrying current:

$\overline{){\mathbf{B}}{\mathbf{=}}\frac{{\mathbf{\mu}}_{\mathbf{0}}\mathbf{i}}{\mathbf{2}\mathbf{\pi}\mathbf{r}}}$

Wires carrying current attract each other if the current is flowing in the same direction. The force is repulsive if current flows in opposite directions.

The forces on wire 2 are; F_{1} repulsive (downward) and F_{3}, repulsive (upward).

Assume that in (Figure 1) *I* = 12A and *d* = 42cm .

What is the magnitude of the force on the second wire?

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