Equivalent resistance for 2 resistors in parallel:
Equivalent resistance for resistors in series:
Req = R + (R)(R)/(R + R) = R + R/2 = 1.5R
Req = (1.5)(4.50) = 6.75Ω
In the circuit of Fig. E26.15, each resistor represents a light bulb. Let R1 = R2 = R3 = 4.50 Ω and ε = 9.00 V.
(a) What is the current in each of the remaining bulbs R1, R2, and R3?
(b) What is the power dissipated in each of the remaining bulbs?
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