The capacitance of a parallel plate capacitor:
The charge stored on a capacitor:
Energy stored by a capacitor:
The electric field in a parallel plate capacitor:
C0 = ε0A/l
C = kε0A/l
C/C0 = kε0A/l ÷ ε0A/l = k
Given a parallel-plate capacitor with plates of area A separated by a distance l. Consider the quantities, (i) capacitance C, (ii) magnitude E of the electric field between the plates, (iii) magnitude of the charge Q on the plates, (iv) potential difference ΔV between the plates, and (v) energy U stored in the capacitor
Assume we apply a given potential difference ΔV0 to the plates.
Suppose we had not changed the geometry of the capacitor but had filled the space between the plates with a dielectric of dielectric constant, K while keeping the charge Q on the pates unchanged. How would that affect the quantities (i) - (v)?
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