The capacitance of a parallel plate capacitor:
The charge stored on a capacitor:
Energy stored by a capacitor:
The electric field in a parallel plate capacitor:
C0 = ε0A/l
C = ε0A/2l
C/C0 = (ε0A/2l)/(ε0A/l) = 1/2
Given a parallel-plate capacitor with plates of area A separated by a distance l. Consider the quantities, (i) capacitance C, (ii) magnitude E of the electric field between the plates, (iii) magnitude of the charge Q on the plates, (iv) potential difference ΔV between the plates, and (v) energy U stored in the capacitor
Assume we apply a given potential difference ΔV0 to the plates.
Suppose we had double the plate separation while keeping the charge on the plates constant. Calculate the quantities (i) - (v) for this case, and express each in terms of its original value. (Obviously, Q = Q0).
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