The capacitance of a parallel plate capacitor:
The charge stored on a capacitor:
Energy stored by a capacitor:
The electric field in a parallel plate capacitor:
Using the expression for the capacitance:
C0 = ε0A/l
C = ε0A/2l
C/C0 = (ε0A/2l)/(ε0A/l) = 1/2
Given a parallel-plate capacitor with plates of area A separated by a distance l. Consider the quantities, (i) capacitance C, (ii) magnitude E of the electric field between the plates, (iii) magnitude of the charge Q on the plates, (iv) potential difference ΔV between the plates, and (v) energy U stored in the capacitor
Assume we apply a given potential difference ΔV0 to the plates. Suppose we double the plate separation while keeping the potential difference constant, calculate the quantities (i) - (v), for this case, and express each in terms of the original value, e.g., C = 2C0, E = (1/4)E0, etc. (Obviously, ΔV = ΔV0).
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