# Problem: Consider a steel guitar string of initial length L = 1.00 m and cross-sectional area A=0.500 mm2. The Young's modulus of the steel is Y = 2.0 × 1011 Pa. How far (ΔL) would such a string stretch under a tension of 1500 N?

###### FREE Expert Solution

Young's modulus:

$\overline{)\begin{array}{rcl}{\mathbf{Y}}& {\mathbf{=}}& \frac{\mathbf{F}\mathbf{/}\mathbf{A}}{\mathbf{∆}\mathbf{L}\mathbf{/}\mathbf{L}}\end{array}}$

A = 0.500 mm2(10-3m/1mm)2 = 5.0 × 10-7 m

1Pa = 1N/m2

###### Problem Details

Consider a steel guitar string of initial length L = 1.00 m and cross-sectional area A=0.500 mm2. The Young's modulus of the steel is Y = 2.0 × 1011 Pa. How far (ΔL) would such a string stretch under a tension of 1500 N?

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