# Problem: Ten identical steel wires have equal lengths Land equal "spring constants" k. The wires are slightly twisted together, so that the resultant wire has length Land is 10 times as thick as each individual wire. What is the"spring constant" of the resulting wire?    a.0.1k   b.k   c. 10k   d. 100k

###### FREE Expert Solution

Equivalent spring constant for parallel springs:

$\overline{){{\mathbf{k}}}_{\mathbf{e}\mathbf{q}}{\mathbf{=}}{{\mathbf{k}}}_{{\mathbf{1}}}{\mathbf{+}}{{\mathbf{k}}}_{{\mathbf{2}}}{\mathbf{+}}{\mathbf{.}}{\mathbf{.}}{\mathbf{.}}{\mathbf{+}}{{\mathbf{k}}}_{{\mathbf{N}}}}$

For equal k:

k = Nk

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###### Problem Details

Ten identical steel wires have equal lengths Land equal "spring constants" k. The wires are slightly twisted together, so that the resultant wire has length Land is 10 times as thick as each individual wire. What is the"spring constant" of the resulting wire?
a.0.1k
b.k
c. 10k
d. 100k