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# Problem: An amoeba is 0.305 cm away from the 0.300 cm- focal length objective lens of a microscope.(a) An eyepiece with a 2.00-cm focal length is placed 20.0 cm from the objective. Where is the final image?(b) What angular magnification is produced by the eyepiece?(c) Suppose the objective lens of the microscope had a magnification of - 60 before placing the eyepiece from the objective, what is the overall magnification?

###### FREE Expert Solution

Lens equation:

$\overline{)\frac{\mathbf{1}}{{\mathbit{s}}_{\mathbit{o}}}{\mathbf{+}}\frac{\mathbf{1}}{{\mathbit{s}}_{\mathbit{i}}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbit{f}}}$

Magnification:

$\overline{){\mathbf{m}}{\mathbf{=}}\frac{{\mathbf{h}}_{\mathbf{i}}}{{\mathbf{h}}_{\mathbf{o}}}{\mathbf{=}}{\mathbf{-}}\frac{{\mathbf{s}}_{\mathbf{i}}}{{\mathbf{s}}_{\mathbf{o}}}}$

(a)

The object distance so from the objective lens will be:

soe = 20 - 18.30 = 1.7 cm

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###### Problem Details

An amoeba is 0.305 cm away from the 0.300 cm- focal length objective lens of a microscope.
(a) An eyepiece with a 2.00-cm focal length is placed 20.0 cm from the objective. Where is the final image?
(b) What angular magnification is produced by the eyepiece?
(c) Suppose the objective lens of the microscope had a magnification of - 60 before placing the eyepiece from the objective, what is the overall magnification?