v•F = (-102.98i - 54.20 j)(−4.00×10−7 i+7.60×10−7 j)
A particle with charge − 6.00 nC is moving in a uniform magnetic field B⃗ =−( 1.23 T )k^. The magnetic force on the particle is measured to be F⃗ =−( 4.00×10−7 N )i^+( 7.60×10−7 N )j^.
1-Calculate the scalar product v⃗ ⋅F⃗ , given that v = -(102.98 m/s)i - (54.20 m/s)j
2-What is the angle between v⃗ and F⃗ ? Give your answer in degrees.
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