Force on Moving Charges & Right Hand Rule Video Lessons

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Problem: A particle with charge −6.00 nC is moving in a uniform magnetic field B⃗ =−( 1.23 T )k^. The magnetic force on the particle is measured to be F⃗ =−( 4.00×10−7 N )i^+( 7.60×10−7 N )j^.1-Calculate the x-component of the velocity of the particle.2-Calculate the y-component of the velocity of the particle.

FREE Expert Solution

Magnetic force:

F=qvB

F=q(vxi^+vyj^+vzk^)×(Bxi^+Byj^+Bzk^)=q(vxi^+vyj^+vzk^)×(0i^+0j^-1.23k^)=q(i^j^k^vxvyvk00-1.23)=q[(-1.23vy-0)i + (0-(-1.23vx)j) + (0 + 0)k)=(-6.00×10-9)(-1.23vyi^+1.23vxj^)

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Problem Details

A particle with charge −6.00 nC is moving in a uniform magnetic field B⃗ =−( 1.23 T )k^. The magnetic force on the particle is measured to be F⃗ =−( 4.00×10−7 N )i^+( 7.60×10−7 N )j^.

1-Calculate the x-component of the velocity of the particle.

2-Calculate the y-component of the velocity of the particle.

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