Mirror Equation Video Lessons

Concept

# Problem: A student notices that the image produced from a large concave mirror of a distant skyscraper (h = 84m) is inverted and the magnitude of the height is 1.29 m tall. The image is located d 181 cm in front of the mirror. a. Write an expression for the distance between the mirror and the skyscraper?b. Numerically, what is the distance in meters?c. Numerically, what is the focal point of the mirror in cm?

###### FREE Expert Solution

Magnification:

$\overline{){\mathbf{m}}{\mathbf{=}}\frac{{\mathbf{h}}_{\mathbf{i}}}{{\mathbf{h}}_{\mathbf{o}}}{\mathbf{=}}{\mathbf{-}}\frac{{\mathbf{s}}_{\mathbf{i}}}{{\mathbf{s}}_{\mathbf{o}}}}$

Mirror equation:

$\overline{)\frac{\mathbf{1}}{{\mathbit{s}}_{\mathbit{o}}}{\mathbf{+}}\frac{\mathbf{1}}{{\mathbit{s}}_{\mathbit{i}}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbit{f}}}$

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###### Problem Details
A student notices that the image produced from a large concave mirror of a distant skyscraper (h = 84m) is inverted and the magnitude of the height is 1.29 m tall. The image is located d 181 cm in front of the mirror.

a. Write an expression for the distance between the mirror and the skyscraper?
b. Numerically, what is the distance in meters?
c. Numerically, what is the focal point of the mirror in cm?