The distance traveled by the electron is expressed as:

$\overline{){\mathbf{y}}{\mathbf{=}}{\mathbf{v}}{\mathbf{t}}}$

**(a)**

In 1 second, the distance traveled by the electron is:

y = v_{av}t

y = (2.20 × 10^{6})(1) = 2.20 × 10^{6}m

The radius of the electron's orbit:

r = d/2 = (1.0 × 10^{-10})/2 = 5.0 × 10^{-11} m

The planetary model of the atom pictures electrons orbiting the atomic nucleus much as planets orbit the Sun. In this model you can view hydrogen, the simplest atom, as having a single electron in a circular orbit 1.0x10^{-10} in diameter.

(a) If the average speed of the electron in this orbit is known to be 2.20x10^{6} m/s , calculate the number of revolutions per second it makes about the nucleus.

(b) What is the electron's average velocity?

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