Change in the electric potential:
ΔU = (Dq - Dqcosθ0)E = DqE - DqEcosθ0
Change in kinetic energy:
ΔK = (1/2)Iωmax2
In this situation, the potential and kinetic energies are equal. So we have:
(1/2)Iωmax2 = DqE - DqEcosθ0
Consider an electric dipole located in a region with an electric field of magnitude E pointing in the positive y direction. The positive and negative ends of the dipole have charges +q and -q, respectively, and the two charges are a distance D apart. The dipole has moment of inertia I about its center of mass. The dipole is released from angle θ=θ0 and it is allowed to rotate freely.
What is ωmax, the magnitude of the dipole's angular velocity when it is pointing along the y-axis?
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