Electric Fields in Capacitors Video Lessons

Concept

# Problem: Suppose you have an electric field between two parallel conducting plates separated by 2.4 cm and having a potential difference (voltage) between them of 1.8 × 104 V. What is the strength of such an electric field in newtons per coulomb?

###### FREE Expert Solution

Potential difference:

$\overline{){\mathbf{∆}}{\mathbf{V}}{\mathbf{=}}{\mathbf{E}}{\mathbf{d}}}$

Therefore, E = ΔV/d

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###### Problem Details

Suppose you have an electric field between two parallel conducting plates separated by 2.4 cm and having a potential difference (voltage) between them of 1.8 × 104 V. What is the strength of such an electric field in newtons per coulomb?