Circular Motion of Charges in Magnetic Fields Video Lessons

Concept

# Problem: A particle with a charge of q = -5.50 nC is moving in a uniform magnetic field of B⃗ =( -1.23 T ) z^.The magnetic force on the particle is measured to be F⃗ =( −7.60×10−7 N )y^.Calculate vx, the x component of the velocity of the particle.

###### FREE Expert Solution

The magnetic force on a charged particle is given by:

$\overline{){\mathbf{F}}{\mathbf{=}}{\mathbf{q}}{\mathbf{\left(}}{\mathbit{v}}{\mathbf{×}}{\mathbf{B}}{\mathbf{\right)}}}$

This is a cross product.

The resultant force will have only one component in the y-direction.

The velocity in the y-direction is zero.

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###### Problem Details

A particle with a charge of q = -5.50 nC is moving in a uniform magnetic field of B⃗ =( -1.23 T ) z^.The magnetic force on the particle is measured to be F⃗ =( −7.60×10−7 N )y^.

Calculate vx, the x component of the velocity of the particle.