Force:

$\overline{){\mathbf{F}}{\mathbf{=}}{\mathbf{q}}{\mathbf{E}}}$

**Part (a)**

Since E = (2/11)Ay

F = (2/11)qAy

Work done:

dW=FdyW=-∫y1y2(211qAy)dy\=-211qA(d22)=-qAd211

A particle of charge q > 0 moves in a uniform electric field E under no external force for a total distance d starting from rest

Part (a) Suppose the field is varying according to E = (2/11) Ayj, where y is the vertical coordinate. The charge q travels from point y_{1} to point y_{2}, where the total traveled distance is d. Taking y_{1} = 0, enter an expression for the potential difference that the charge traverses in terms of the available symbols

Part (c) If the charge q = 4.72 C, distance, d = 82m and the constant A = 14.7 V/m^{2}, how much work, in Jules, is done on the charge while it travels the potential difference in part (a)?

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