A = (3.25×10⁻³ cm²)(10⁻² m/1 cm)² = 3.25×10⁻⁷ m²
L = 10m
R = 1.345Ω
ρ = RA/L
R=ρL/A where L is the length and A is the cross-sectional area of the wire. From the wire in question 4, the length of the wire is 10m, the cross-sectional area of the wire is 3.25×10-3 cm2. The relative uncertainty of L and A are both 10%. What are the resistivity of the wire and its uncertainty? The value of R is 1.345 ohms
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