Current:

$\overline{){\mathbf{i}}{\mathbf{\left(}}{\mathbf{t}}{\mathbf{\right)}}{\mathbf{=}}{{\mathbf{i}}}_{{\mathbf{0}}}{{\mathbf{e}}}^{\mathbf{-}\frac{\mathbf{R}}{\mathbf{L}}\mathbf{t}}}$

**Part (a)**

i(0.1s) = i_{0}e^{(-R/L)t} = (ε/R)(e^{(-R/L)t}) = (4.5/258)(e^{(-258/2.2)0.1}) = 1.41 × 10^{-7} A

The current in the circuit at t = 0.1 s is 1.41 × 10^{-7} A

An RL circuit is shown on the right. L = 2.2 J, R = 258 Ω, ε = 4.5 V

Switch A is closed at t = 0.

After a long time, when the current reaches its steady value, open switch A and close switch B at the same time. Count this moment as t = 0.

Part (a) Calculate the numerical value of *I* at *t* = 0.1 s in amperes.

Part (b) Calculate the numerical value of *I* at *t* = L/R s in amperes.

Part (c) Calculate the current, in amperes, after an infinite time.

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