Current:

$\overline{){\mathbf{i}}{\mathbf{\left(}}{\mathbf{t}}{\mathbf{\right)}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}\frac{\mathbf{\epsilon}}{\mathbf{R}}{\mathbf{(}}{\mathbf{1}}{\mathbf{}}{\mathbf{-}}{\mathbf{}}{{\mathbf{e}}}^{\mathbf{-}\frac{\mathbf{R}}{\mathbf{L}}\mathbf{t}}{\mathbf{)}}}$

**Part (a)**

i(0.1s) = (ε/R)(1 - e^{(-R/L)t}) = (4.5/258)(1 - e^{(-258/2.2)0.1}) = 0.0174 A

An RL circuit is shown on the right. L = 2.2 J, R = 258 Ω, ε = 4.5 V. Switch A is closed at t = 0.**(a)** Calculate the numerical value of *I* at *t* = 0.1 s in amperes.**(b)** Calculate the numerical value of *I* at *t* = L/R s in amperes.**(c)** Calculate the numerical value of *I*, in amperes, when t goes to infinity.

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