Momentum is conserved for two particles undergoing a perfectly elastic head-on collision.
Since the billiard balls are of the same mass, we will consider the mass of either ball to be m.
Conservation of momentum:
mv1i + mv2i = mv1f = mv2f
Two billiard balls of equal mass undergo a perfectly elastic head-on collision. If one ball's initial speed was 2.20 m/s , and the other's was 3.50 m/s in the opposite direction, what will be their speeds after the collision?
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