Thin Lens And Lens Maker Equations Video Lessons

Concept

# Problem: An object is placed 10 cm to the left of a converging lens that has a focal length of 20 cm. Describe what the resulting image will look like (i.e) image distance, magnification , upright or inverted images, real or virtual images?)

###### FREE Expert Solution

Lens equation:

$\overline{)\frac{\mathbf{1}}{{\mathbit{s}}_{\mathbit{o}}}{\mathbf{+}}\frac{\mathbf{1}}{{\mathbit{s}}_{\mathbit{i}}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbit{f}}}$

Magnification:

$\overline{){\mathbf{m}}{\mathbf{=}}{\mathbf{-}}\frac{{\mathbf{s}}_{\mathbf{i}}}{{\mathbf{s}}_{\mathbf{o}}}}$

From the Lens equation:

1/si = 1/f - 1/so

90% (413 ratings)
###### Problem Details

An object is placed 10 cm to the left of a converging lens that has a focal length of 20 cm. Describe what the resulting image will look like (i.e) image distance, magnification , upright or inverted images, real or virtual images?)

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Thin Lens And Lens Maker Equations concept. You can view video lessons to learn Thin Lens And Lens Maker Equations. Or if you need more Thin Lens And Lens Maker Equations practice, you can also practice Thin Lens And Lens Maker Equations practice problems.