Electric Field Video Lessons

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Problem: Two positive point charges q are placed on the x-axis, one at x = a and one at x = -a.(a) Find the magnitude and direction of the electric field at x = 0.(b) Derive an expression for the electric field at points on the x -axis. Use your result to graph the x-component of the electric field as a function of x, for values of x between -4a and +4a.

FREE Expert Solution

Electric field:

E=14πε0qr2

(a)

The point x = 0 is the midpoint between the two positive charges. The electric field is zero at this point. 

E = Ea + E-a

E=14πε0qa2i+14πε0q(-a)2(-i)=14πε0qa2i-14πε0qa2i

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Problem Details

Two positive point charges q are placed on the x-axis, one at x = a and one at x = -a.
(a) Find the magnitude and direction of the electric field at x = 0.
(b) Derive an expression for the electric field at points on the x -axis. Use your result to graph the x-component of the electric field as a function of x, for values of x between -4a and +4a.

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