# Problem: A parallel-plate air capacitor has a capacitance of 920 pF. The charge on each plate is 3.90 μC. What is the potential difference between the plates? Express your answer with the appropriate units. Part B If the charge is kept constant, what will be the potential difference between the plates if the separation is doubled? Express your answer with the appropriate units. Part C How much work is required to double the separation? Express your answer with the appropriate units (mJ)

###### FREE Expert Solution

Potential difference:

$\overline{){\mathbf{V}}{\mathbf{=}}\frac{\mathbf{Q}}{\mathbf{C}}}$

Part A

V = 3.90 × 10-6/920 × 10-12 = 4239 V

84% (273 ratings) ###### Problem Details

A parallel-plate air capacitor has a capacitance of 920 pF. The charge on each plate is 3.90 μC. What is the potential difference between the plates? Express your answer with the appropriate units.

Part B If the charge is kept constant, what will be the potential difference between the plates if the separation is doubled? Express your answer with the appropriate units.

Part C How much work is required to double the separation? Express your answer with the appropriate units (mJ)