V = 3.90 × 10-6/920 × 10-12 = 4239 V
A parallel-plate air capacitor has a capacitance of 920 pF. The charge on each plate is 3.90 μC. What is the potential difference between the plates? Express your answer with the appropriate units.
Part B If the charge is kept constant, what will be the potential difference between the plates if the separation is doubled? Express your answer with the appropriate units.
Part C How much work is required to double the separation? Express your answer with the appropriate units (mJ)
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Parallel Plate Capacitors concept. You can view video lessons to learn Parallel Plate Capacitors. Or if you need more Parallel Plate Capacitors practice, you can also practice Parallel Plate Capacitors practice problems.
What professor is this problem relevant for?
Based on our data, we think this problem is relevant for Professor Adams' class at AU.