Equivalent resistance for 2 resistors in parallel:

$\overline{){{\mathbf{R}}}_{{\mathbf{eq}}}{\mathbf{=}}\frac{{\mathbf{R}}_{\mathbf{1}}{\mathbf{R}}_{\mathbf{2}}}{{\mathbf{R}}_{\mathbf{1}}\mathbf{+}{\mathbf{R}}_{\mathbf{2}}}}$

Equivalent resistance for resistors in series:

$\overline{){{\mathbf{R}}}_{{\mathbf{eq}}}{\mathbf{=}}{{\mathbf{R}}}_{{\mathbf{1}}}{\mathbf{+}}{{\mathbf{R}}}_{{\mathbf{2}}}{\mathbf{+}}{\mathbf{.}}{\mathbf{.}}{\mathbf{.}}{\mathbf{+}}{{\mathbf{R}}}_{{\mathbf{n}}}}$

Current:

$\overline{){\mathbf{i}}{\mathbf{=}}\frac{\mathbf{V}}{\mathbf{R}}}$

In the figure, three resistors are connected to a voltage source so that *R*_{2} and *R*_{3} are in parallel with one another and that combination is in series with *R*_{1}. Calculate *I*_{3} using the potential and resistances given in the figure.

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Combining Resistors in Series & Parallel concept. You can view video lessons to learn Combining Resistors in Series & Parallel. Or if you need more Combining Resistors in Series & Parallel practice, you can also practice Combining Resistors in Series & Parallel practice problems.

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Based on our data, we think this problem is relevant for Professor Turgut's class at OKSTATE.