# Problem:  To understand Ampère's law and its application. Ampère's law is often written Part A The integral on the left is a. the integral throughout the chosen volume b. the surface integral over the open surface. c. the surface integral over the closed surface bounded by the loop. d. the line integral along the closed lop e. the line integral tom stat to finishPart B The circle on the integral means that B(r) must be integrated a. over a circle or a sphere b. along any closed path that you choose. c. along the path of a closed physical conductor d. over the surface bounded by the current-carrying wire.

###### FREE Expert Solution

Ampere's circuital law can be expressed as line integral as:

$\overline{){\mathbf{\oint }}\stackrel{\mathbf{⇀}}{\mathbf{B}}{\mathbf{\left(}}{\mathbf{r}}{\mathbf{\right)}}{\mathbf{·}}{\mathbf{d}}\stackrel{\mathbf{⇀}}{\mathbf{l}}{\mathbf{=}}{{\mathbf{\mu }}}_{{\mathbf{0}}}{{\mathbf{I}}}_{{\mathbf{enc}}}}$

Part A

The line integral of a closed loop is equal to µ0 times the enclosed current.

98% (165 ratings) ###### Problem Details

To understand Ampère's law and its application. Ampère's law is often written

Part A The integral on the left is

a. the integral throughout the chosen volume

b. the surface integral over the open surface.

c. the surface integral over the closed surface bounded by the loop.

d. the line integral along the closed lop

e. the line integral tom stat to finish

Part B The circle on the integral means that B(r) must be integrated

a. over a circle or a sphere

b. along any closed path that you choose.

c. along the path of a closed physical conductor

d. over the surface bounded by the current-carrying wire.