Work From Electric Force Video Lessons

Concept

# Problem: A point charge q1= +2.40μC is held stationary at the origin. A second point charge q2= -4.30μC moves from the point x = 0.175 m ,  y = 0 m , to the point x = 0.275 m , y = 0.275 m .How much work is done by the electric force on q2?

###### FREE Expert Solution

Work done in moving the charge:

$\overline{){\mathbf{W}}{\mathbf{=}}{\mathbf{k}}{{\mathbf{q}}}_{{\mathbf{1}}}{{\mathbf{q}}}_{{\mathbf{2}}}{\mathbf{\left(}}\frac{\mathbf{1}}{{\mathbf{r}}_{\mathbf{1}}}{\mathbf{-}}\frac{\mathbf{1}}{{\mathbf{r}}_{\mathbf{2}}}{\mathbf{\right)}}}$

The initial distance between the two charges is given by:

${\mathbit{r}}_{\mathbf{i}}\mathbf{=}\sqrt{{\mathbf{\left(}\mathbf{0}\mathbf{.}\mathbf{175}\mathbf{-}\mathbf{0}\mathbf{\right)}}^{\mathbf{2}}\mathbf{+}{\mathbf{\left(}\mathbf{0}\mathbf{-}\mathbf{0}\mathbf{\right)}}^{\mathbf{2}}}$

ri = 0.175 m

###### Problem Details

A point charge q1= +2.40μC is held stationary at the origin. A second point charge q2= -4.30μC moves from the point x = 0.175 m ,  y = 0 m , to the point x = 0.275 m , y = 0.275 m .

How much work is done by the electric force on q2?