Where Q is the flow rate, A is the cross-sectional area, and v is the velocity.
A1 = πr12 = (πd12)/4
Water flows through a water hose at a rate of Q1 = 620 cm3/s, the diameter of the hose is d1 = 2.48 cm. A nozzle is attached to the water hose. The water leaves the nozzle at a velocity of v2 = 14.8 m/s.
a. Enter an expression for the cross-sectional area of the hose, A1, in terms of its diameter, d1.
b. Calculate the numerical value of A1, in square centimeters.
c. Enter an expression for the speed of the water in the hose, v1, in terms of the volume flow rate Q1 and cross-sectional area A1.
d.Calculate the speed of the water in the hose, v1 in meters per second.
e.Enter an expression for the cross-sectional area of the nozzle, A2, in terms of v1, v2 and A1.
f. Calculate the cross-sectional area of the nozzle, A2 in square centimeters.
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Fluid Flow & Continuity Equation concept. You can view video lessons to learn Fluid Flow & Continuity Equation. Or if you need more Fluid Flow & Continuity Equation practice, you can also practice Fluid Flow & Continuity Equation practice problems.