The magnitudes of v_{0} and v_{2} are the same. Speed does not include the direction.

The figure shows the trajectory of a golf ball in projectile motion over level ground. The time t_{0} = 0 s corresponds to the moment just after the ball is launched from position x_{0} = 0 m, y_{0} = 0 m. Its initial velocity (launch velocity) is *v*_{0}. Two other points along the trajectory are indicated in the figure. At time t_{1} (with velocity *v*_{1}), the ball reaches the peak of its trajectory. Its position at this moment is denoted by (x_{1},y_{1}) or (x_{1},y_{max}), since it is at its maximum height. At time t_{2} (with velocity *v*_{2}), just before the ball touches the ground again, its position is (x_{2},y_{2}) or (x_{max},y_{2}), since it is at its maximum horizontal range.

How do the speeds v_{0}, v_{1}, and v_{2} (at times t_{0}, t_{1}, and t_{2}) compare?

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