The width of central maximum is given by:

$\overline{){\mathbf{w}}{\mathbf{=}}\frac{\mathbf{2}\mathbf{\lambda}\mathbf{R}}{\mathbf{d}}}$

A 0.50-mm-wide slit is illuminated by light of wavelength 500 nm. What is the width of the central maximum on a screen 2.0 m behind the slit? Please answer in mm.

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