Equivalent resistance for 2 resistors in parallel:

$\overline{){{\mathbf{R}}}_{{\mathbf{eq}}}{\mathbf{=}}\frac{{\mathbf{R}}_{\mathbf{1}}{\mathbf{R}}_{\mathbf{2}}}{{\mathbf{R}}_{\mathbf{1}}\mathbf{+}{\mathbf{R}}_{\mathbf{2}}}}$

Equivalent resistance for resistors in series:

$\overline{){{\mathbf{R}}}_{{\mathbf{eq}}}{\mathbf{=}}{{\mathbf{R}}}_{{\mathbf{1}}}{\mathbf{+}}{{\mathbf{R}}}_{{\mathbf{2}}}{\mathbf{+}}{\mathbf{.}}{\mathbf{.}}{\mathbf{.}}{\mathbf{+}}{{\mathbf{R}}}_{{\mathbf{n}}}}$

Ohm's law:

$\overline{){\mathbf{V}}{\mathbf{=}}{\mathbf{i}}{\mathbf{R}}}$

Resistors c and d are in series:

R_{cd} = R_{1} + R_{2} = 5 + 5 = 10Ω

Resistor b is in parallel with resistors R_{cd}:

R_{bcd} = (R_{1}R_{2})/(R_{1} + R_{2}) = (10 × 10)/(10 + 10) = 5Ω

Resistor a is in series R_{bcd}:

R_{eq} = R_{1} + R_{2} = 5 + 5 = 10Ω

Find the current through resistor A in the figure.

Find the potential difference across resistor A in the figure.

Find the current through resistor B in the figure.

Find the potential difference across resistor B in the figure.

Find the current through resistor C in the figure.

Find the potential difference across resistor C in the figure.

Find the current through resistor D in the figure.

Find the potential difference across resistor D in the figure.

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