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# Problem: A hollow, conducting sphere with an outer radius of 0.250 m and an inner radius of 0.200 m has a uniform surface charge density of +6.37×10−6 C/m2A charge of −0.500μC is now introduced at the center of the cavity inside the sphere. (a) What is the new charge density on the outside of the sphere? (b) Calculate the strength of the electric field just outside the sphere. (c) What is the electric flux through a spherical surface just inside the inner surface of the sphere?

###### FREE Expert Solution

Charge density outside the sphere:

$\overline{){\mathbf{\sigma }}{\mathbf{=}}\frac{\mathbf{Q}}{\mathbf{4}\mathbf{\pi }{{\mathbf{r}}_{\mathbf{o}}}^{\mathbf{2}}}}$

(a)

The charge density:

σ = (-0.500 × 10-6)/(4π)(0.2502) = - 6.37 × 10-7 C/m2

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###### Problem Details

A hollow, conducting sphere with an outer radius of 0.250 m and an inner radius of 0.200 m has a uniform surface charge density of +6.37×10−6 C/m2

A charge of −0.500μC is now introduced at the center of the cavity inside the sphere.

(a) What is the new charge density on the outside of the sphere?

(b) Calculate the strength of the electric field just outside the sphere.

(c) What is the electric flux through a spherical surface just inside the inner surface of the sphere?

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Gauss' Law concept. You can view video lessons to learn Gauss' Law. Or if you need more Gauss' Law practice, you can also practice Gauss' Law practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Lannon's class at NOTRE DAME.