When r and F are perpendicular, θ = 90°. Whe r and F are parallel, θ = 0°.
τ1 = r•Fsinθ = (L/4)(2F)(sin 90) = (LF)/2
τ2 = r•Fsinθ = (L/2)(F)(sinθ2) = (LFsinθ2)/2 or (LF/2)sinθ2
Six forces, each of magnitude either F or 2F, are applied to a door as seen from above in Figure 6. Rank in order, from smallest to largest, the six torques τ1 to τ6 about the hinge.
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