For 2 capacitors in series, the equivalent capacitance is:
For capacitors in parallel, the equivalent capacitance is:
The charge stored by a capacitor:
C2 and C3 are in series:
C23 = (30)(30)/(30 + 30) = 15 μF
The initial charge Q0 = C1V = (15 × 10-6)(100) = 1.5 × 10-3 C
This charge will distribute equally among capacitor C1 and C23.
Initially, the switch in the figure is in position A and capacitors C2 and C3 are uncharged. Then the switch is flipped to position B. (Figure 1)
A) Afterward, what is the charge on C1 capacitor? (I tried doing 15 times 100 for 1500 uC but it won't get accepted for some reason. Help!!)
B) Afterward, what is the potential difference across C1 capacitor?
C) Afterward, what is the charge on C2 capacitor?
D) Afterward, what is the potential difference across C2 capacitor?
E) Afterward, what is the charge on C3 capacitor?
F) Afterward, what is the potential difference across C3 capacitor?
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Our tutors have indicated that to solve this problem you will need to apply the Capacitors in AC Circuits concept. You can view video lessons to learn Capacitors in AC Circuits. Or if you need more Capacitors in AC Circuits practice, you can also practice Capacitors in AC Circuits practice problems.
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