The electric field inside the wire:

$\overline{){\mathbf{E}}{\mathbf{=}}\frac{\mathbf{V}}{\mathbf{L}}}$, where V is the potential difference across the wire and L is the length of the wire.

Current density caused by electric field inside conductor:

$\overline{){\mathbf{J}}{\mathbf{=}}{\mathbf{\sigma}}{\mathbf{E}}}$, where σ is the conductivity.

Current density is also expressed as:

$\overline{){\mathbf{J}}{\mathbf{=}}\frac{\mathbf{i}}{\mathbf{A}}}$

A 20 cm long nichrome wire is connected across the terminals of a 1.5 V battery.

a. What is the electric field inside the wire?

b. What is the current density inside the wire?

c. If the current in the wire is 1.0 A, what is the wires diameter?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Microscopic View of Current concept. You can view video lessons to learn Microscopic View of Current. Or if you need more Microscopic View of Current practice, you can also practice Microscopic View of Current practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Nakajima's class at UCF.