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Problem: The coefficient of kinetic friction between the 2.0 kg block infigure and the table is 0.300.What is the acceleration of the 2.0 kg block?

FREE Expert Solution

Let's consider the following free-body diagrams.

For 1.0 kg block:

For 2.0 kg block:

For 3.0 kg block:

Newton's second law:

ΣF=ma

From Newton's second law for the 1.0 kg block:

T1 - m1g = m1a

For the 2.0 kg block:

T2 - (T1 + fk) = m2a, 

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Problem Details

The coefficient of kinetic friction between the 2.0 kg block infigure and the table is 0.300.

What is the acceleration of the 2.0 kg block?

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Based on our data, we think this problem is relevant for Professor Beer's class at MIAMIOH.