# Problem: The coefficient of kinetic friction between the 2.0 kg block infigure and the table is 0.300.What is the acceleration of the 2.0 kg block?

###### FREE Expert Solution

Let's consider the following free-body diagrams.

For 1.0 kg block:

For 2.0 kg block:

For 3.0 kg block:

Newton's second law:

$\overline{){\mathbf{\Sigma }}{\mathbf{F}}{\mathbf{=}}{\mathbf{m}}{\mathbf{a}}}$

From Newton's second law for the 1.0 kg block:

T1 - m1g = m1a

For the 2.0 kg block:

T2 - (T1 + fk) = m2a,

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###### Problem Details

The coefficient of kinetic friction between the 2.0 kg block infigure and the table is 0.300.

What is the acceleration of the 2.0 kg block?

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Systems of Objects: Inclined Planes + Friction concept. If you need more Systems of Objects: Inclined Planes + Friction practice, you can also practice Systems of Objects: Inclined Planes + Friction practice problems.