Position Functions and Instantaneous Velocity Video Lessons

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Problem: The position of a particle is given by the function x=(2t3−9t2+12)m, where t is in s.1.) At what time or times is vx = 0m/s?2.) What is the particle's position at this times?

FREE Expert Solution

Velocity:

vx=dxdt

1)

From the given position, the velocity is:

vx=ddt(2t3-9t2+12)=6t2-18t

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Problem Details

The position of a particle is given by the function x=(2t3−9t2+12)m, where t is in s.

1.) At what time or times is vx = 0m/s?

2.) What is the particle's position at this times?

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