Centripetal force:

$\overline{){{\mathbf{F}}}_{{\mathbf{C}}}{\mathbf{=}}\frac{\mathbf{m}{\mathbf{v}}^{\mathbf{2}}}{\mathbf{r}}}$

Frictional force:

$\overline{){{\mathbf{f}}}_{{\mathbf{r}}}{\mathbf{=}}{\mathbf{\mu}}{\mathbf{m}}{\mathbf{g}}}$

A 1500 kg car drives at 30 m/s around a flat circular track 300 \rm m in diameter.

a. What are the magnitude and direction of the net force on the car?

Since the net force is equivalent to the force of static friction, your answer to Part a is the magnitude.

b. Based on this value, what is the minimum coefficient μ_{s} of static friction between the road and the car?

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