Centripetal Forces Video Lessons

Concept

Problem: A 1500 kg car drives at 30 m/s around a flat circular track 300 \rm m in diameter. a. What are the magnitude and direction of the net force on the car?Since the net force is equivalent to the force of static friction, your answer to Part a is the magnitude. b. Based on this value, what is the minimum coefficient μs of static friction between the road and the car?

FREE Expert Solution

Centripetal force:

$\overline{){{\mathbf{F}}}_{{\mathbf{C}}}{\mathbf{=}}\frac{\mathbf{m}{\mathbf{v}}^{\mathbf{2}}}{\mathbf{r}}}$

Frictional force:

$\overline{){{\mathbf{f}}}_{{\mathbf{r}}}{\mathbf{=}}{\mathbf{\mu }}{\mathbf{m}}{\mathbf{g}}}$

Problem Details

A 1500 kg car drives at 30 m/s around a flat circular track 300 \rm m in diameter.

a. What are the magnitude and direction of the net force on the car?
Since the net force is equivalent to the force of static friction, your answer to Part a is the magnitude.

b. Based on this value, what is the minimum coefficient μs of static friction between the road and the car?

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