We're told that al the wires are made of the same material and are of the same diameter.
From Kirchhoff's junction rule, the current I1 is equally divided into two parts.
Suppose I1 = I, then we'll have:
I2 = I3 = I/2
All wires in the figure are made of the same material and have the same diameter. Rank in order, from largest to smallest,the currents I1 to I4. Explain.
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