We can solve this problem using Ohm's law and the law of conservation of charge.
In the first circuit, the current is flowing towards point 1.
The potential difference across the points 1, 2, and 3 are the same.
From Ohm's law, current, I = V/R.
Thus, from the conservation of charge, currents at points 1, 2, and 3 are equal.
I1 = I2 = I3 = ΔV/R
The two circuits in (Figure 1) use identical batteries and wires of equal diameters. Rank in order, from largest to smallest, the currents I1 to I7 at points 1 to 7.
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