The de Broglie wavelength:

$\overline{){\mathbf{\lambda}}{\mathbf{=}}\frac{\mathbf{h}}{\mathbf{p}}}$, where h is Plank's constant and p is the momentum of the particle.

For the purposes of precise explanation, let's consider a baseball of a mass of 0.2kg that moves with a speed of 15 m/s.

The de Broglie wavelength of such a ball is in the order of 10^{-34} m.

When you throw a baseball, its de Broglie wavelength is

(a) the same size as the ball

(b) about the same size as an atom

(c) about the same size as atom’s nucleus

(d) much smaller than the size of an atom’s nucleus

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