Coulomb's Law (Electric Force) Video Lessons

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Problem: A simple and common technique for accelerating electrons is shown in Figure 18.55, where there is a uniform electric field between two plates. Electrons are released, usually a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to continue moving. (a) Calculate the acceleration of the electron if the field strength is 2.50x104 N/C.(b) Explain why the electron will not be pulled back to the positive plate once it moves through the hole.

FREE Expert Solution

From Coulomb's law, the electrostatic force is:

F=qE

Newton's second law:

F=ma

(a)

From the two equations, we have, ma = qE

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Problem Details

A simple and common technique for accelerating electrons is shown in Figure 18.55, where there is a uniform electric field between two plates. Electrons are released, usually a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to continue moving. 


(a) Calculate the acceleration of the electron if the field strength is 2.50x104 N/C.

(b) Explain why the electron will not be pulled back to the positive plate once it moves through the hole.


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