Maximum height reached:

$\overline{){{\mathbf{h}}}_{\mathbf{m}\mathbf{a}\mathbf{x}}{\mathbf{=}}\frac{{{\mathbf{v}}_{\mathbf{0}}}^{\mathbf{2}}}{\mathbf{2}\mathbf{g}}}$

We'll also use the kinematic equation:

$\overline{){\mathbf{\u2206}}{\mathit{y}}{\mathbf{=}}{\mathbf{}}{{\mathit{v}}}_{{\mathbf{0}}}{\mathit{t}}{\mathbf{-}}{\frac{1}{2}}{\mathit{g}}{{\mathit{t}}}^{{\mathbf{2}}}}$

Steelhead trout migrate up stream to spawn. Occasionally they need to leap up small waterfalls to continue their journey. Fortunately, steelhead are remarkable jumpers, capable of leaving the water at a speed of 8.0 m/s.

a. What is the maximum height a steelhead trout can jump?

b. Leaving the water at 8.0 m/s, the trout lands on top of the water fall 1.8 m high. How long was it in the air?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Positive (Upward) Launch concept. You can view video lessons to learn Positive (Upward) Launch. Or if you need more Positive (Upward) Launch practice, you can also practice Positive (Upward) Launch practice problems.

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Based on our data, we think this problem is relevant for Professor Villa-Vargas' class at GS.