Vector Magnitude:

$\overline{)\mathbf{\left|}\stackrel{\mathbf{\rightharpoonup}}{\mathit{A}}\mathbf{\right|}{\mathbf{=}}\sqrt{{{\mathit{A}}_{\mathit{x}}}^{\mathbf{2}}\mathbf{+}{{\mathit{A}}_{\mathit{y}}}^{\mathbf{2}}}}$

Direction:

$\overline{){\mathbf{tan}}{\mathit{\theta}}{\mathbf{=}}\frac{{\mathit{A}}_{\mathit{y}}}{{\mathit{A}}_{\mathit{x}}}}$

In the y-direction:

F_{y} = F_{1}cos(30°) - F_{2} sin(45°)

F_{y} = (250)cos(30°) - (375)sin(45°) = - 48.66 lb

Determine the magnitude of the resultant force F_{R} = F_{1} + F_{2} and its direction, measured counterclockwise from the positive x-axis.

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