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# Problem: A 2.0-cm-diameter spider is 2.0 m from a wall.Determine the focal length and position (measured from the wall) of a lens that will make a half-size image of the spider on the wall.

###### FREE Expert Solution

Lens equation:
$\overline{)\frac{\mathbf{1}}{{\mathbit{s}}_{\mathbit{o}}}{\mathbf{+}}\frac{\mathbf{1}}{{\mathbit{s}}_{\mathbit{i}}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbit{f}}}$

Magnification:

$\overline{){\mathbf{m}}{\mathbf{=}}\frac{{\mathbf{h}}_{\mathbf{i}}}{{\mathbf{h}}_{\mathbf{o}}}{\mathbf{=}}{\mathbf{-}}\frac{{\mathbf{s}}_{\mathbf{i}}}{{\mathbf{s}}_{\mathbf{o}}}}$

The distance between the object and the image is:

so + si = 2.0 m

Magnification, m = -si/so = 1/2

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###### Problem Details

A 2.0-cm-diameter spider is 2.0 m from a wall.

Determine the focal length and position (measured from the wall) of a lens that will make a half-size image of the spider on the wall.

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Thin Lens And Lens Maker Equations concept. You can view video lessons to learn Thin Lens And Lens Maker Equations. Or if you need more Thin Lens And Lens Maker Equations practice, you can also practice Thin Lens And Lens Maker Equations practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Pau's class at UCLA.