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# Problem: When an ion channel opens in a cell wall (see Problem 40), monovalent (charge e) ions flow through the channel at a rate of 2.9x107 ions/s. (a) What is the current through the channel? (b) The potential difference across the ion channel is 88 mV. What is the power dissipation in the channel?

###### FREE Expert Solution

The amount of current flowing through the channel is found by:

Power:

$\overline{){\mathbf{P}}{\mathbf{=}}{\mathbf{i}}{\mathbf{∆}}{\mathbf{V}}}$

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###### Problem Details

When an ion channel opens in a cell wall (see Problem 40), monovalent (charge e) ions flow through the channel at a rate of 2.9x107 ions/s. (a) What is the current through the channel? (b) The potential difference across the ion channel is 88 mV. What is the power dissipation in the channel?