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Problem: When an ion channel opens in a cell wall (see Problem 40), monovalent (charge e) ions flow through the channel at a rate of 2.9x107 ions/s. (a) What is the current through the channel? (b) The potential difference across the ion channel is 88 mV. What is the power dissipation in the channel?

FREE Expert Solution

The amount of current flowing through the channel is found by:

i=(ions per second)×(charge of each ion)

Power:

P=iV

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Problem Details

When an ion channel opens in a cell wall (see Problem 40), monovalent (charge e) ions flow through the channel at a rate of 2.9x107 ions/s. (a) What is the current through the channel? (b) The potential difference across the ion channel is 88 mV. What is the power dissipation in the channel?

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