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# Problem: A certain simple pendulum has a period on the earth of 1.50s.What is its period on the surface of Mars, where g=3.71m/s2?

###### FREE Expert Solution

Periodic time for a pendulum:

$\overline{){\mathbf{T}}{\mathbf{=}}{\mathbf{2}}{\mathbf{\pi }}\sqrt{\frac{\mathbf{l}}{\mathbf{g}}}}$

The length of the pendulum l is constant.

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###### Problem Details

A certain simple pendulum has a period on the earth of 1.50s.

What is its period on the surface of Mars, where g=3.71m/s2?

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Simple Harmonic Motion of Pendulums concept. You can view video lessons to learn Simple Harmonic Motion of Pendulums. Or if you need more Simple Harmonic Motion of Pendulums practice, you can also practice Simple Harmonic Motion of Pendulums practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Guo's class at HCC.